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In the diagram below, the area of angle BCD is 60. What is the area of angle BAD?

 

Guest Nov 9, 2017
edited by Guest  Nov 9, 2017
 #1
avatar+87571 
+1

Using my other answer that BC  = 8...we have a trapezoid

 

Area of trapezoid  =  ( height / 2  ) * ( sum of the bases )

 

Area  of trapezoid  =  ( BC / 2) * ( CD + BA )

 

Area of Trapezoid  = (8 / 2) * ( 15 + 9 )

 

Area of Trapezoid  =  4 * (24)  =    96

 

So....

 

Area of BAD  = 

 

Area of Trapezoid  - Area of  BCD 

 

               96           -          60                =    36

 

 

cool cool cool

CPhill  Nov 9, 2017
 #2
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You are always right. thx again.

Guest Nov 9, 2017
 #3
avatar+87571 
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LOL!!!!...not always....!!!!

 

 

cool cool cool

CPhill  Nov 9, 2017

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