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A ball travels on a parabolic path in which the height (in feet) is given by the expression -16^2 +32t +15, where t is the time after launch. What is the maximum height of the ball, in feet?

 Oct 22, 2019
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-16^2 +32t +15

 

The max height occurs when t  =   (-32) / (2 * -16)  =   -32/-32  =   1

 

So.....the max height is

 

-16(1)^2  + 32(1)  + 15 =

 

-16  +  32  + 15  =

 

31 ft

 

 

cool cool cool

 Oct 22, 2019

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