A ball travels on a parabolic path in which the height (in feet) is given by the expression -16^2 +32t +15, where t is the time after launch. What is the maximum height of the ball, in feet?
-16^2 +32t +15
The max height occurs when t = (-32) / (2 * -16) = -32/-32 = 1
So.....the max height is
-16(1)^2 + 32(1) + 15 =
-16 + 32 + 15 =
31 ft
