Find the intersection of the lines $9x-4y=30$ and $7x+y=11.$ Express your answer as an ordered pair $(x,y).$
9x-4y=30, 7x+y=11.
We convert these to y-intercept form first.
9x-4y=30
4y=9x-30
y=9/4x-30/4
7x+y=11
y=-7x+11
Then set them equal to each other.
9/4x-30/4=-7x+11
37/4x=74/4
x=2
Then y=-3.
Therefore the point of intersection is (2, -3).