+0  
 
0
4
1
avatar+952 

Find the coordinates of the center of the circle.

 

 Apr 23, 2024
 #1
avatar+128794 
+1

x^2 + y^2   = r^2

(x + 2)^2 + ( y  -1)^2   = r^2            set these equal  for r^2

 

x^2 + y^2 =  x^2 + 4x +4 + y^2 - 2y + 1

 

4x - 2y  = -5     (1)

 

 

And

 

x^2 + y^2 = r^2

(x +3)^2 + ( y  -2)^2  = r^2           set these equal for r^2

 

x^2 + y^2  =  x^2 + 6x + 9 + y^2 - 4y + 4

 

6x - 4y =  -13      (2)

 

Multiply (1)  throughby -2  and add to (2)   and we have

 

-2x = -3

x =3/2

 

To find y, use (1)

4(3/2)  - 2y = -5

 

6 - 2y = -5

11 = 2y

y = 11/2

 

(x, y) = ( 3/2 , 11/ 2)

 

 

cool cool cool

 Apr 23, 2024

2 Online Users

avatar
avatar