How many integers satisfy the inequality \(x(3x-4) \le \frac{6x^2 - 3x + 5}{10}\)?

I got to the point, \(-\frac{1}{8}\le \:x\le \frac{5}{3}\). I don't rember how to find the amount of numbers between the inequality. Help.

I hope this makes sence to the person reading this. thx.

Guest Aug 9, 2019