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How many integers satisfy the inequality \(x(3x-4) \le \frac{6x^2 - 3x + 5}{10}\)?

 

I got to the point, \(-\frac{1}{8}\le \:x\le \frac{5}{3}\). I don't rember how to find the amount of numbers between the inequality. Help.

I hope this makes sence to the person reading this. thx.

 Aug 9, 2019
 #1
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You really ought to be able to glance at that inequality (the bottom one) and immediately see the two integers that satisfy it.

 Aug 9, 2019
edited by Rom  Aug 9, 2019
 #2
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I know but the question is asking all of the numbers between the inequality I don't know if i counted them all correctly

Guest Aug 9, 2019
 #3
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never mind I thought that the question was asking something different I got the correct answer. thanks for pointing that out for me. 

 Aug 9, 2019

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