+0  
 
+1
48
3
avatar

Find the equation of the parabolic asymptote of the graph of

I used long division and got 2x^2+8x+30 but that wasn't right do I have to account for the remainder as well?

 May 9, 2020
 #1
avatar+20906 
+1

When I did the long division, I got:  2x2 + 8x + 15 ...

 May 10, 2020
 #2
avatar+65 
+1

I think thats wrong as well hmm I'm stumpted

 May 10, 2020
 #3
avatar+109519 
+1

I assume this is what is wanted.

 

\(y=\frac{2x^2-3}{x^2-4x+1}=2x^2+8x+30+\frac{112x-33}{x^2-4x+1}\\~\\~\\ \displaystyle\lim_{x\rightarrow\pm\infty}y=2x^2+8x+30\)

 

 

Here is the graph:

 

https://www.desmos.com/calculator/hjkeir8rpl

 

 

Edit:

Sorry, I see you think that is not correct. It looks right to me.   indecision

 May 10, 2020
edited by Melody  May 10, 2020

13 Online Users

avatar