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If y= (x^2 + 2x + 8)/(x^2 - 4x + 4), at what value of x will there be a vertical asymptote?

 Oct 18, 2022
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If y= (x^2 + 2x + 8)/(x^2 - 4x + 4), at what value of x will there be a vertical asymptote?  

 

 

You get an asymptote when the denominator is zero. 

 

(x^2 - 4x + 4) factors to (x – 2)(x – 2) so you get your asymptote at x = 2  

 Oct 18, 2022

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