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You are given that x is directly proportional to y^3, and y is inversely proportional to \(\sqrt{z}\). If the value of x is 3 when z is 12, what is the value of x when z is equal to 75? 

 Apr 29, 2019
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x =k * y^3/sqrt(z)
3 = k * y^3 /sqrt(12)
x = k * y^3/sqrt(75), solve for k, x, y
k =2.5,  x=0.34641  and  y^3 =6/5 =1.2. OR:

k=sqrt(12),  x =6/5 and   y^3 =3
Note : Somebody should check this! Thanks.

 Apr 30, 2019
edited by Guest  Apr 30, 2019

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