The solutions of the equation 30z^2-7z-20=68 are z=r and z=s. Find (r+3)(s+3).
By the quadratic formula, the roots are (7 \pm sqrt(2449))/60. Plugging in these value gives us
(r + 3)(s + 3) = ((7 + sqrt(2449))/60 + 3)((7 - sqrt(2449))/60 + 3) = 271/30
