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Find the value of a so that the lines with the given equations are perpendicular.

y=2x+13

 

 6y+ax=6

 Jan 3, 2023
 #2
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Whn lines are perpendicular, their slopes mutltiply to -1 in slope intercept form

We have: 

y=2x+13

6y+ax =6

 

y= 2x+13

6y = -ax+6

 

y=2x+13

y=-(a/6)x+1

 

-(a/6) = -1/2

a=3

 Jan 3, 2023

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