Find the value of a so that the lines with the given equations are perpendicular.
y=2x+13
6y+ax=6
+394 Whn lines are perpendicular, their slopes mutltiply to -1 in slope intercept form
We have:
y=2x+13
6y+ax =6
y= 2x+13
6y = -ax+6
y=2x+13
y=-(a/6)x+1
-(a/6) = -1/2
a=3
