x / 2 - 2 / [ x + 1 ] = 1 get a common denominator on the left
[ x [ x + 1 ] - 2*2 ) / [ 2 ( x + 1) ] = 1
[ x^2 + x - 4] / [ 2x + 2 ] =1 multiply both sides by 2x + 2
x^2 + x - 4 = 2x + 2 subtract 2x, 2 from both sides
x^2 - x - 6 = 0 factor
(x - 3) ( x + 2) = 0
Set both factors to 0 and solve for x and we get that
x = 3 or x = -2
8 ( x + 3)^2 8 ( x + 3)^2
__________ = _ * _______ = 4 (x + 3) = 4x + 12
2 ( x + 3) 2 ( x + 3)