+0  
 
+1
39
2
avatar+77 

https://web2.0calc.com/questions/help-plz_60142

 May 1, 2020
 #1
avatar+111327 
+1

3.    -3 + 3i

 

z = √ [ (-3)^2 + 3^2]  =  √ 18   =  3√2

 

arctan (3/-3)  =  arctan (-1)  = -  pi/4   = θ

 

However....this is located in Q2  so  θ =  3pi/4

 

So

 

z = 3√2 cis( 3pi/4)

 

 

cool cool cool

 May 1, 2020
 #2
avatar+111327 
0

4  was answered  by geno, here : https://web2.0calc.com/questions/divide_11

 

 

cool cool cool

 May 1, 2020

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