https://web2.0calc.com/questions/help-plz_60142
3. -3 + 3i
z = √ [ (-3)^2 + 3^2] = √ 18 = 3√2
arctan (3/-3) = arctan (-1) = - pi/4 = θ
However....this is located in Q2 so θ = 3pi/4
So
z = 3√2 cis( 3pi/4)
4 was answered by geno, here : https://web2.0calc.com/questions/divide_11
