Find length BC.
Taking a really long time to download the diagram........
yup, but if I remember correctly, it was a triangle with one angle being 30, one side being 13, and the other... being... uhhh... 8? I think.
Image below
Use cosine law BC^2 = 8^2 + 13^2 - 2 ( 8)(13) cos 30 You can finish.... remember : this is to find BC2
+37159 
