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William has six more nickels than dimes. Combined, the total value of the coins is $1.35. How many of each does he have?

 Dec 21, 2018

Best Answer 

 #2
avatar+98130 
+1

Let the number of dimes = N

Then the number of nickels  = N + 6

 

So

 

number of dimes * value of each + number of nickels * value of each = total money

 

So  we have

 

N * .10  +   (N + 6) * .05   =  1.35    simplify

 

.10N  + 05N + .30  = 1.35

 

.15N + .30  = 1.35      subtract  .30 from both sides

 

.15N = 1.05      divide both sides by .15

 

N = 7    (dimes)

And the number of nickels  =  N + 6  = 7 + 6  =  13

 

 

cool cool cool

 Dec 21, 2018
edited by CPhill  Dec 21, 2018
 #1
avatar+3994 
0

11 nickels and 5 dimes, sorry for no explanation.

 Dec 21, 2018
 #2
avatar+98130 
+1
Best Answer

Let the number of dimes = N

Then the number of nickels  = N + 6

 

So

 

number of dimes * value of each + number of nickels * value of each = total money

 

So  we have

 

N * .10  +   (N + 6) * .05   =  1.35    simplify

 

.10N  + 05N + .30  = 1.35

 

.15N + .30  = 1.35      subtract  .30 from both sides

 

.15N = 1.05      divide both sides by .15

 

N = 7    (dimes)

And the number of nickels  =  N + 6  = 7 + 6  =  13

 

 

cool cool cool

CPhill Dec 21, 2018
edited by CPhill  Dec 21, 2018

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