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# Help plz

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William has six more nickels than dimes. Combined, the total value of the coins is \$1.35. How many of each does he have?

Dec 21, 2018

#2
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Let the number of dimes = N

Then the number of nickels  = N + 6

So

number of dimes * value of each + number of nickels * value of each = total money

So  we have

N * .10  +   (N + 6) * .05   =  1.35    simplify

.10N  + 05N + .30  = 1.35

.15N + .30  = 1.35      subtract  .30 from both sides

.15N = 1.05      divide both sides by .15

N = 7    (dimes)

And the number of nickels  =  N + 6  = 7 + 6  =  13   Dec 21, 2018
edited by CPhill  Dec 21, 2018

#1
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11 nickels and 5 dimes, sorry for no explanation.

Dec 21, 2018
#2
+1

Let the number of dimes = N

Then the number of nickels  = N + 6

So

number of dimes * value of each + number of nickels * value of each = total money

So  we have

N * .10  +   (N + 6) * .05   =  1.35    simplify

.10N  + 05N + .30  = 1.35

.15N + .30  = 1.35      subtract  .30 from both sides

.15N = 1.05      divide both sides by .15

N = 7    (dimes)

And the number of nickels  =  N + 6  = 7 + 6  =  13   CPhill Dec 21, 2018
edited by CPhill  Dec 21, 2018