William has six more nickels than dimes. Combined, the total value of the coins is $1.35. How many of each does he have?

Guest Dec 21, 2018

#2**+1 **

Let the number of dimes = N

Then the number of nickels = N + 6

So

number of dimes * value of each + number of nickels * value of each = total money

So we have

N * .10 + (N + 6) * .05 = 1.35 simplify

.10N + 05N + .30 = 1.35

.15N + .30 = 1.35 subtract .30 from both sides

.15N = 1.05 divide both sides by .15

N = 7 (dimes)

And the number of nickels = N + 6 = 7 + 6 = 13

CPhill Dec 21, 2018

#2**+1 **

Best Answer

Let the number of dimes = N

Then the number of nickels = N + 6

So

number of dimes * value of each + number of nickels * value of each = total money

So we have

N * .10 + (N + 6) * .05 = 1.35 simplify

.10N + 05N + .30 = 1.35

.15N + .30 = 1.35 subtract .30 from both sides

.15N = 1.05 divide both sides by .15

N = 7 (dimes)

And the number of nickels = N + 6 = 7 + 6 = 13

CPhill Dec 21, 2018