A ball is thrown in the air from a platform that is 48 feet above the ground with an initial vertical velocity of 32 feet per second. The height of the ball, in feet, can be represented by the function h(t) = -16t^2 +32t +48, where t is the time, in seconds, since the balls was thrown. How long does it take the ball to reach 55 feet?
+37153 55 = -16t^2 + 32t + 48
-16t^2 + 32t - 7 = 0 Now use Quadratic Formula to solve for the t's whenthe height = 55 ,
the smaller t will be on the way UP and the larger will be on the way back down
