+0

# Help Plzz

+1
150
2

1

The logo for a new company is a circle divided into 24 equally sized sectors. Six of the sectors are white, and the others are different colors.

The area of one of the white sectors is  13π/50 inches squared.

2.

What is the area of a triangle whose sides measure 13 inches, 15 inches, and 24 inches?

Apr 2, 2020

#1
+2

180  / 24  =  15°  for each sector

So....the white ones  occupy  6 * 15°   =  90°   =  area  of (1/4)  of the circle

So  we  have   that

6 *(13/50) pi  =  (1/4) pi * radius ^2     divide both sides  by pi

(78/50)   =       (1/4)  * radius ^2          multiply  both sides  by 4

6.24  =  r^2               take the sqrt

sqrt (6/24)   = r  ≈  2.50  in   Apr 2, 2020
#2
+1

What is the area of a triangle whose sides measure 13 inches, 15 inches, and 24 inches?

s  =semi-perimeter =   [   13  +  15   +  24  ]   /  2    =    [  52  ]  /   2   =   26

Area  =

√   [s (s - a) (s - b) (s - c)  ]          where a,b,c  = triangle's sides

√   [26  ( 26 - 13) (26 - 15) (26 -24)  ]  =

√  [ 26  * 13 * 11  * 2  ]   =

√  [ 13 * 2 * 13 * 11 * 2 ]  =

13*2√ 11

26√ 11  in ^2   Apr 2, 2020