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How many ways are there to divide a red bracelet, a yellow bracelet, a green bracelet, and a black bracelet among 4 people if each person can receive any number of bracelets, including  0 ? Each bracelet must be given to someone.

 Dec 28, 2018
 #1
avatar+4220 
+1

See here: https://web2.0calc.com/questions/hlelp-plzzz

 Dec 28, 2018
 #2
avatar+18311 
+1

Rom answered this yesterday.......see your previous posting......

 Dec 28, 2018
 #3
avatar+18311 
+1

R    Y    G    B

1     1     1    1          Person 1 gets all 4  R Y G B

1     1     1    2       Person 1 gets  R Y G and person 2 gets B  (& Peeps 3 &4 get 0: No Bracelet)

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4     4    4     4            where the numbers represent the person who gets the   R Y G B bracelet....

 

 

So there is   4 * 4 * 4 * 4  =256  combos 

                                   ( if a person is not reperesented by a number, it is zero: No Bracelet)

 Dec 28, 2018
edited by Guest  Dec 28, 2018
edited by Guest  Dec 28, 2018
 #4
avatar+4220 
+2

This is also distinguishability with duplicates, so \(4^4=\boxed{256}.\)

.
 Dec 28, 2018

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