How many ways are there to divide a red bracelet, a yellow bracelet, a green bracelet, and a black bracelet among 4 people if each person can receive any number of bracelets, including 0 ? Each bracelet must be given to someone.
+37156 Rom answered this yesterday.......see your previous posting......
+37156 R Y G B
1 1 1 1 Person 1 gets all 4 R Y G B
1 1 1 2 Person 1 gets R Y G and person 2 gets B (& Peeps 3 &4 get 0: No Bracelet)
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4 4 4 4 where the numbers represent the person who gets the R Y G B bracelet....
So there is 4 * 4 * 4 * 4 =256 combos
( if a person is not reperesented by a number, it is zero: No Bracelet)
