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The quadratic $x^2-3x+1$ can be written in the form $(x+b)^2+c$, where $b$ and $c$ are constants. What is $b+c$?

 Feb 4, 2021
 #1
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x^2 - 3x + 1 = (x - 3)^2 - 8, so b + c = (-3) + (-8) = -11.

 Feb 4, 2021
 #2
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Nice try, but the answer is wrong.

Guest Feb 4, 2021
 #3
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x^2   -3x  + 1       complete the square on x

 

Take 1/2  of  -3....=  -3/2     square this =  9/4    ....add and subtract it

 

x^2  -3x  +   9/4  + 1    -9/4           factor the first three terms, simplify the rest

 

(x - 3/2)^2   -   5/4

 

b + c  =    -3/2  - 5/4   =  --6/4  - 5/4  =  -11/4

 

 

cool cool cool

 Feb 4, 2021

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