The quadratic $x^2-3x+1$ can be written in the form $(x+b)^2+c$, where $b$ and $c$ are constants. What is $b+c$?
x^2 - 3x + 1 = (x - 3)^2 - 8, so b + c = (-3) + (-8) = -11.
Nice try, but the answer is wrong.
x^2 -3x + 1 complete the square on x
Take 1/2 of -3....= -3/2 square this = 9/4 ....add and subtract it
x^2 -3x + 9/4 + 1 -9/4 factor the first three terms, simplify the rest
(x - 3/2)^2 - 5/4
b + c = -3/2 - 5/4 = --6/4 - 5/4 = -11/4
