The polynomial f(x) has degree 3. If f(0) = 4, f(1)= -2 , f(3) = 0, and f(3) = 28, then what are the x -intercepts of the graph of f(x)?
Let the polynomial be in the form \(y = ax^3 + bx^2 + cx + d\).
From \(f(3) = 0\) and \(f(3) = 28\), we have: \(27a + 9b + 3c + d = 28 = 0\), which can't be true.
This means that there is no polynomial...