The polynomial f(x) has degree 3. If f(0) = 4, f(1)= -2 , f(3) = 0, and f(3) = 28, then what are the x -intercepts of the graph of f(x)?
Let the polynomial be in the form y=ax3+bx2+cx+d.
From f(3)=0 and f(3)=28, we have: 27a+9b+3c+d=28=0, which can't be true.
This means that there is no polynomial...