Two different numbers are selected simultaneously and at random from the set {1,2,3,4,5,6,7,8,9}. What is the probability that the positive difference between the two numbers is 3 or greater? Express your answer as a common fraction.
+2668 You forgot 6 and 9, making the probability \({21 \over 36} = \color{brown}\boxed{7 \over 12}\)
+344 https://web2.0calc.com/questions/help-please_55057 here's a similar problem
+118690 Thanks hipie, that question was similar. (I did give you a point but someone else deducted one, you can give yourself a point though.)
I just want to play with it myself
14,15,16,17,18,19,
25,26,27,28,29
36,37,38,39,
47,48,49
58,59
These are the acceptable pairs there are 6+5+4+3+2 = 20 of them
9C2=36 possible pairs
P(success)=20/36 = 5/9
+2668 You forgot 6 and 9, making the probability \({21 \over 36} = \color{brown}\boxed{7 \over 12}\)
