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Two different numbers are selected simultaneously and at random from the set {1,2,3,4,5,6,7,8,9}. What is the probability that the positive difference between the two numbers is 3 or greater? Express your answer as a common fraction.

 Apr 20, 2022

Best Answer 

 #3
avatar+1370 
+2

You forgot 6 and 9, making the probability \({21 \over 36} = \color{brown}\boxed{7 \over 12}\)

 Apr 20, 2022
 #1
avatar+79 
+4

https://web2.0calc.com/questions/help-please_55057 here's a similar problem

 Apr 20, 2022
 #2
avatar+117117 
+4

Thanks hipie, that question was similar.  (I did give you a point but someone else deducted one, you can give yourself a point though.) 

 

I just want to play with it myself

 

14,15,16,17,18,19,

25,26,27,28,29

36,37,38,39,

47,48,49

58,59

These are the acceptable pairs there are  6+5+4+3+2 = 20 of them

9C2=36 possible pairs

 

P(success)=20/36  = 5/9

 Apr 20, 2022
edited by Melody  Apr 20, 2022
 #3
avatar+1370 
+2
Best Answer

You forgot 6 and 9, making the probability \({21 \over 36} = \color{brown}\boxed{7 \over 12}\)

BuilderBoi  Apr 20, 2022
 #4
avatar+117117 
0

You are right, I did .   Thanks Builderboi! 

Melody  Apr 21, 2022

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