Two different numbers are selected simultaneously and at random from the set {1,2,3,4,5,6,7,8,9}. What is the probability that the positive difference between the two numbers is 3 or greater? Express your answer as a common fraction.

Guest Apr 20, 2022

#3**+1 **

You forgot 6 and 9, making the probability \({21 \over 36} = \color{brown}\boxed{7 \over 12}\)

BuilderBoi Apr 20, 2022

#2**+3 **

Thanks hipie, that question was similar. (I did give you a point but someone else deducted one, you can give yourself a point though.)

I just want to play with it myself

14,15,16,17,18,19,

25,26,27,28,29

36,37,38,39,

47,48,49

58,59

These are the acceptable pairs there are 6+5+4+3+2 = 20 of them

9C2=36 possible pairs

P(success)=20/36 = 5/9

Melody Apr 20, 2022

#3**+1 **

Best Answer

You forgot 6 and 9, making the probability \({21 \over 36} = \color{brown}\boxed{7 \over 12}\)

BuilderBoi
Apr 20, 2022