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# help probability

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Two different numbers are selected simultaneously and at random from the set {1,2,3,4,5,6,7,8,9}. What is the probability that the positive difference between the two numbers is 3 or greater? Express your answer as a common fraction.

Apr 20, 2022

#3
+2665
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You forgot 6 and 9, making the probability $${21 \over 36} = \color{brown}\boxed{7 \over 12}$$

Apr 20, 2022

#1
+330
+5

https://web2.0calc.com/questions/help-please_55057 here's a similar problem

Apr 20, 2022
#2
+118571
+3

Thanks hipie, that question was similar.  (I did give you a point but someone else deducted one, you can give yourself a point though.)

I just want to play with it myself

14,15,16,17,18,19,

25,26,27,28,29

36,37,38,39,

47,48,49

58,59

These are the acceptable pairs there are  6+5+4+3+2 = 20 of them

9C2=36 possible pairs

P(success)=20/36  = 5/9

Apr 20, 2022
edited by Melody  Apr 20, 2022
#3
+2665
+1
You forgot 6 and 9, making the probability $${21 \over 36} = \color{brown}\boxed{7 \over 12}$$