A point (x,y) is randomly selected such that 0 <= x <= 3 and 0 <= y <= 6. What is the probability that x + y <= 5? Express your answer as a common fraction.
+2401 You can do it geometrically.
The area of x + y <= 5 is 10.5
The total area is 18.
10.5/18 = 21/36 = 7/12
=^._.^=
+128408 See the graph here : https://www.desmos.com/calculator/xkhp2wh2sd
The total feasible area is a 3 x 6 rectangle = 18 units^2
The area of concern is a triangle with a height and base of 3....and a 3 x 2 rectangle
This area is (3*3)/2 + 3 x 2 = 9/2 + 6 = 21 / 2
The probability = (21/2) / 18 = 21 / 36 = 7 / 12
