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Ten $6$-sided dice are rolled. What is the probability that exactly three of the dice show an odd number? Express your answer as a decimal rounded to the nearest thousandth.

 Aug 7, 2023
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We have a binomial probabiity  problem....3 of the  dice  must  show odd  and each one has a probability of (1/2) of that....the other 7 each have a probability of (1/2) of showing even.....we need to  choose any  3 of the  10 to show  odd...so we have

 

C(10,3) (1/2)^3 (1/2)^7  =  15 /128 ≈ .117

 

 

cool cool cool

 Aug 7, 2023

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