1. Find the ordered pair (s, t) that satisfies the system (s/2)+5t=3 3t-6s=9
If anyone can help me with this problem, thank you. The answer is in fractions for both
We can solve the first equation for s, getting s=3/2−5t. Substituting this into the second equation, we get: 3t−6((3/2−5t))=9⇒−27t+9=−9⇒ t = 2/3.
Substituting this back into the equation for s, we get s = 3/2−5(2/3) = 1/6
Therefore, the solution is (s,t) = (1/6,2/3).
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