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If x, y, and z are positive integers such that 6xyz+30xy+21xz+2yz+105x+10y+7z=812, find x+y+z

 Aug 4, 2022
 #1
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x + y + z = 12

 Aug 4, 2022
 #2
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no, is not

 Aug 4, 2022
 #3
avatar+124676 
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x =2  y=2  z  = 6

 

x+ y + z =10

 

 

cool cool cool

 Aug 5, 2022

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