The equation y = -6t^2 + 51t describes the height (in feet) of a projectile launched from the surface of Mars at 51 feet per second. In how many seconds will the projectile first reach 118 feet in height?
118 = - 6t^2 + 51t
-6t^2 + 51t - 118 = 0
use quadratic formula to find two values of 't' ....the smaller one is the FIRST time the projectile is at 118 ft (on the way UP)
a = -6 b = 51 c=-118
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
