The equation y = -6t^2 + 51t describes the height (in feet) of a projectile launched from the surface of Mars at 51 feet per second. In how many seconds will the projectile first reach 118 feet in height?

118 = - 6t^2 + 51t

-6t^2 + 51t - 118 = 0

use quadratic formula to find two values of 't' ....the smaller one is the FIRST time the projectile is at 118 ft (on the way UP)

a = -6 b = 51 c=-118

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)