Give an example of a quadratic function that has zeroes at x = 2 and x = -4, and that takes the value 6 when x = 3. Write your answer in expanded form "ax^2 + bx + c", where a,b,c are replaced by appropriate numbers.
+36916 You are given zeroes at 2 and -4
so the quadratic is of the form y = a ( x-2)(x+4)
y = a ( x^2 + 2x - 8) when x = 3 we need y = 6
(a )(9 + 6 - 8 ) = 6
a =6/7
y =6/7 x^2 +12/7 x -48/7
