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Give an example of a quadratic function that has zeroes at x = 2 and x = -4, and that takes the value 6 when x = 3. Write your answer in expanded form "ax^2 + bx + c", where a,b,c are replaced by appropriate numbers.

 Apr 17, 2021
 #1
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You are given zeroes at 2 and -4

so the quadratic is of the form   y =   a ( x-2)(x+4)     

                                             y = a  ( x^2 + 2x - 8)       when x = 3 we need y = 6

                                                      (a )(9 + 6 - 8 ) = 6

                                                            a =6/7

 

y =6/7 x^2   +12/7 x -48/7            

 Apr 17, 2021

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