The quadratic x^2 - 6x + 60 can be written in the form (x + b)^2 + c, where b and c are constants. What is b + c?
This is much like completing the square for x
x^2 - 6x + 60 =
(x-3)2 - 9 +60 =
(x-3)2 + 51 You can finish, no?