Note 1/a^2 + 1/b^2 = [a^2 + b^2 ] / [ ab ] ^2
The sum of the roots = 11/5 = a + b
Square both sides
121/25 = a^2 + 2ab + b^2
The product of the roots = 4/5 = ab so.....2ab = 8/5 and [ab]^2 = 16/25
So
121/25 = a^2 + 2(4/5) + b^2
121/25 = a^2 + 8/5 + b^2
121/25 - 8/5 = a^2 + b^2
121/25 - 8/5 = a^2 + b^2
121/25 - 40/25 = a^2 + b^2
81/25 = a^2 + b^2
So
1/a^2 + 1/b^2 = [ 81/25] / [ 16/25 ] = 81 / 16