When the expression 3x^2-24x+55-x^2-49 is written in the form a(x+d)^2+e, where a, d, and e are constants, then what is the sum a+d+e?
3x^2 -24x + 55 - x^2 - 49 simplify as
2x^2 - 24x - 6
2 ( x^2 - 12x - 3) complete the square on x inside the parentheses
2 ( x^2 - 12x + 36 - 3 - 36)
2 (x - 6)^2 + 2 (-39)
2 (x - 6)^2 - 78
a + d + e = 2 - 6 - 78 = -82
wait, 55-49 = -6?
