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When the expression 3x^2-24x+55-x^2-49 is written in the form a(x+d)^2+e, where a, d, and e are constants, then what is the sum a+d+e?

 Jun 29, 2022
 #1
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+1

3x^2 -24x + 55 - x^2 - 49      simplify as

 

2x^2 - 24x  -  6

 

2 ( x^2 - 12x - 3)       complete the square on  x inside the parentheses

 

2 ( x^2 - 12x + 36 - 3 - 36)

 

2 (x - 6)^2    + 2 (-39)

 

2 (x - 6)^2  -  78

 

a +  d +  e     =     2 - 6  - 78  =    -82

 

 

cool cool cool

 Jun 29, 2022
 #2
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wait, 55-49 = -6?

Guest Jun 30, 2022

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