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What real value of $t$ produces the smallest value of the quadratic $t^2 -9t - 36 + 13t - 60$?

 Jan 12, 2024

Best Answer 

 #1
avatar+287 
+1

\(t^2+4t-96\)

 

t = -b/2a

t = -4/2

t = -2

 

Plugging in -2 for t, we get:

 

\(4-8-96\)

 

\(-100\)

 

The coordinates of the vertex are (-2,-100)

 

The smallest value of the quadratic is -100

 

 

Answer:  -100

 Jan 12, 2024
 #1
avatar+287 
+1
Best Answer

\(t^2+4t-96\)

 

t = -b/2a

t = -4/2

t = -2

 

Plugging in -2 for t, we get:

 

\(4-8-96\)

 

\(-100\)

 

The coordinates of the vertex are (-2,-100)

 

The smallest value of the quadratic is -100

 

 

Answer:  -100

DS2011 Jan 12, 2024

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