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Triangle ABC has circumcenter O. If AB = 10 and [OAB] = 30 find the circumradius of triangle ABC.

 Nov 26, 2020
 #1
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The circumcenter is the perpendicular bisectors of a side of a triangle intersect.

cos(30)=1/2AB/x

X=1/2AB/cos(30)=5/(sqrt3/2)=10/sqrt3=5.77 units
 

 Nov 26, 2020
 #2
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Triangle ABC has circumcenter O. If AB = 10 and [OAB] = 30 find the circumradius of triangle ABC.

 

AB = 10          [OAB] = 30 u2

 

AB / 2 = 5                (Midpoint on AB is M)

 

OM = 30 / 5 = 6

 

Circumradius        r = sqrt(52 + 62) = √61

 Nov 26, 2020

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