One of the roots of 2x^3-9x^2+13x+k=0 is x=2.Find the other 2 roots. Explain how you got the answer.
One of the roots of 2x^3-9x^2+13x+k=0 is \(x_1=2\).Find the other 2 roots. Explain how you got the answer.
Hello whatdoiputhere!
\((2x ^ 3-9x ^ 2 + 13x + k) \) \(:(x-2)=\) \(2x^2-5x+3\)
\(\underline{2x^3-4x^2}\)
\(-5x^2+13x\)
\(\underline{-5x^2+10x}\)
\(3x+k\)
\(\underline{3x-6}\)
\(0\)
\(k=-6\)
\(2x^2-5x+3=0\\ x^2-2.5x+1.5=0\\ x=1.25\pm \sqrt{1.25^2-1.5}\\ \color{blue}x=1.25\pm0.25\)
\(x\in\{1,1.5,2\}\)
!
One of the roots of 2x^3-9x^2+13x+k=0 is \(x_1=2\).Find the other 2 roots. Explain how you got the answer.
Hello whatdoiputhere!
\((2x ^ 3-9x ^ 2 + 13x + k) \) \(:(x-2)=\) \(2x^2-5x+3\)
\(\underline{2x^3-4x^2}\)
\(-5x^2+13x\)
\(\underline{-5x^2+10x}\)
\(3x+k\)
\(\underline{3x-6}\)
\(0\)
\(k=-6\)
\(2x^2-5x+3=0\\ x^2-2.5x+1.5=0\\ x=1.25\pm \sqrt{1.25^2-1.5}\\ \color{blue}x=1.25\pm0.25\)
\(x\in\{1,1.5,2\}\)
!