HELP QUICK!

One of the roots of 2x^3-9x^2+13x+k=0 is $x_1=2$.Find the other 2 roots. Explain how you got the answer. 

Hello whatdoiputhere!

$(2x ^ 3-9x ^ 2 + 13x + k)$  $:(x-2)=$  $2x^2-5x+3$

 $\underline{2x^3-4x^2}$

          $-5x^2+13x$

          $\underline{-5x^2+10x}$

                           $3x+k$

                           $\underline{3x-6}$

                                     $0$

$k=-6$

$2x^2-5x+3=0\\ x^2-2.5x+1.5=0\\ x=1.25\pm \sqrt{1.25^2-1.5}\\ \color{blue}x=1.25\pm0.25$

$x\in\{1,1.5,2\}$

  !