r and s are the roots of 3x^2 + 4x - 12 = 0. What is r^2+s^2????
HELP!!
Remember Vieta's formulas?
rs = -12/3 = -4
r+s = -4/3
Now, do this:
(r+s)2 = r2 + s2 + 2rs sub in the reds above
(-4/3)2 = r2 + s2 + 2 ( -4)
r2 + s2 = (-4/3)2 + 8 <====== you can finish, yah ?