+0

0
89
3

Suppose that a, b, and c are real numbers such that a/b = sqrt(10)/sqrt(21) and b/c = sqrt(14)/sqrt(15). Find a/c. Completely simplify and rationalize the denominator.

Aug 5, 2022

#1
0

if a/b = sqrt10/sqrt21 then a =sqrt10

if b/c = sqrt14/sqrt15 then c = sqrt15

then a/c = sqrt10/sqrt15

rationalize the denominator means no sqrt in the denominator

to rationalize it, multiply  by 1 using the denominator/denominator as our 1

sqrt10/sqrt15 * Sqrt15/sqrt15

sqrt10*sqrt15/sqrt15*sqrt15

sqrt150/15

5sqrt6/15

sqrt6/3

Aug 5, 2022
edited by Guest  Aug 5, 2022
#3
+2532
+1

That logic is incorrect because they have different denominators. In the first fraction b is $$\sqrt{21}$$ and in the second it is $$\sqrt {14}$$

BuilderBoi  Aug 5, 2022
#2
+2532
0

https://web2.0calc.com/questions/algebra_96607

Aug 5, 2022