What would (A+A^b)^b be?
(A+A^b)^b
=A(1+A^(b-1))^b
That could not be further simplified.
I do not think you can do anything with that.....it is as simplified as you can make it.
Ummmm. I thought of binomial theorem.
\((A+A^b)^b\\ = A^b+\displaystyle C^{b}_{1}A^{2b-1}+C^{b}_{2}A^{3b-2}+C^{b}_{3}A^{4b-3}.......\)
+37084 
