Simplify \(\dfrac{\dfrac{x^2 + 2x - 3}{x - 4}}{\dfrac{2x^2 + 5x - 3}{x^2 - 16}}\)
We get
(x^4+2x^3−19x^2−32x+48)/(2x3−3x2−23x+12) when we make a common denominator and we then we factor to get
((x−1)(x+3)(x+4)(x−4))/((2x−1)(x+3)(x−4)) which simplifies to (x^2+3x−4)/(2x−1) or \(\boxed{\dfrac{x^2+3x−4}{2x−1}}\)
