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Simplify \(\dfrac{\dfrac{x^2 + 2x - 3}{x - 4}}{\dfrac{2x^2 + 5x - 3}{x^2 - 16}}\)

 

 Aug 4, 2020
 #1
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We get 

(x^4+2x^3−19x^2−32x+48)/(2x3−3x2−23x+12) when we make a common denominator and we then we factor to get 

((x−1)(x+3)(x+4)(x−4))/((2x−1)(x+3)(x−4)) which simplifies to (x^2+3x−4)/(2x−1) or \(\boxed{\dfrac{x^2+3x−4}{2x−1}}\)

 Aug 4, 2020

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