+130561 OK......I guess we have
2^(t + 3) = 7^(t - 1) ???? if so........take the log of both sides
log2^(t +3) = log7^(t - 1) and we can write
(t +3) log2 = (t - 1) log 7 simplify
t log2 + 3log2 = tlog7 - log 7
3log2 + log7 = tlog7 - t log2
3log2 + log 7 = t [ log 7 - log2] divide both sides by log 7 - log2
[3log2 + log 7 ] / [ log7 - log2] = t = about 3.2132
+130561 Here's a graphical solution : https://www.desmos.com/calculator/hvjfai7rfa
The solution occurs at about t = 0.91
i think u misunderstood...those are raised to the power............it has somethig to do with log brother.
+130561 OK......I guess we have
2^(t + 3) = 7^(t - 1) ???? if so........take the log of both sides
log2^(t +3) = log7^(t - 1) and we can write
(t +3) log2 = (t - 1) log 7 simplify
t log2 + 3log2 = tlog7 - log 7
3log2 + log7 = tlog7 - t log2
3log2 + log 7 = t [ log 7 - log2] divide both sides by log 7 - log2
[3log2 + log 7 ] / [ log7 - log2] = t = about 3.2132
