Compute \[\frac{1}{2^3 - 2} + \frac{1}{3^3 - 3} + \frac{1}{4^3 - 4} + \dots + \frac{1}{6^3 - 6}.\]
\(\phantom{100^3 - 100}\)
sumfor(n, 2, 6, 1 / (n^3 - n)==It converges to 5 / 21
