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Find the value of  a so that the system has no solutions.

 

y = 11x + 14

2x - 4 = ax + 7 - 4x

 Apr 13, 2022
 #1
avatar+578 
+1

y = 11x + 14

2x - 4 = ax + 7 - 4x

 

y = 11x + 14

y=6x -ax- 11 

 

We need to find the value of \(a\) which makes 6x-ax=11x

 

ax = 11x-6x

a = -5

 

y = 11x + 14

y= 11x - 11 

 

They both done intercept, so the value of \(a\) must be -5

 

Also the check I attached the graph below:

 

https://www.desmos.com/calculator/jfzvbcaqth

 

smileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmileysmiley

 Apr 13, 2022
 #2
avatar+114 
-1

Hold up let me check u out

 Apr 13, 2022
 #3
avatar+578 
+1

Yes pleas, I think I might have messed up somewhere

Vinculum  Apr 13, 2022
edited by Vinculum  Apr 13, 2022

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