Find the value of a so that the system has no solutions.
y = 11x + 14
2x - 4 = ax + 7 - 4x
y = 11x + 14
2x - 4 = ax + 7 - 4x
y = 11x + 14
y=6x -ax- 11
We need to find the value of \(a\) which makes 6x-ax=11x
ax = 11x-6x
a = -5
y = 11x + 14
y= 11x - 11
They both done intercept, so the value of \(a\) must be -5
Also the check I attached the graph below:
https://www.desmos.com/calculator/jfzvbcaqth