A gardener has a circular garden, which he divides into four quadrants. He has four different kinds of flowers, and he wants to assign a flower to each quadrant, so that adjacent quadrants are not planted with the same kind of flower. (Also, the gardener can use the same flower more than once.) How many different gardens are possible?
My bad, let's start again
A can take four flowers, B can take 3
Then there are 3 choices for C.
If C=A there are 3 choices for D
if C!=A there are 2 choices for D
So we have
4 x 3 x (3 + 2x2) = 4 x 3 x 7 = 84