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# help thanks

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Find the smallest possible value of

$$\frac{(y-x)^2}{(y-z)(z-x)} + \frac{(z-y)^2}{(z-x)(x-y)} + \frac{(x-z)^2}{(x-y)(y-z)}$$

where x,y and z are distinct real numbers.

Mar 8, 2020

#1
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The minimum value is -4.

Mar 9, 2020
#2
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+2

Find the smallest possible value of

$$\dfrac{(y-x)^2}{(y-z)(z-x)} + \dfrac{(z-y)^2}{(z-x)(x-y)} + \dfrac{(x-z)^2}{(x-y)(y-z)}$$

where x,y and z are distinct real numbers.

$$\huge {AM \geq GM}$$

$$\begin{array}{|rcll|} \hline \dfrac{\dfrac{(y-x)^2}{(y-z)(z-x)} + \dfrac{(z-y)^2}{(z-x)(x-y)} + \dfrac{(x-z)^2}{(x-y)(y-z)} }{3} &\ge& \sqrt[3]{\dfrac{(y-x)^2}{(y-z)(z-x)} \times \dfrac{(z-y)^2}{(z-x)(x-y)} \times \dfrac{(x-z)^2}{(x-y)(y-z)}} \\ \dfrac{\dfrac{(y-x)^2}{(y-z)(z-x)} + \dfrac{(z-y)^2}{(z-x)(x-y)} + \dfrac{(x-z)^2}{(x-y)(y-z)} }{3} &\ge& \sqrt[3]{ \dfrac{(y-x)^2(z-y)^2(x-z)^2} {(y-x)^2(z-y)^2(x-z)^2} } \\ \dfrac{\dfrac{(y-x)^2}{(y-z)(z-x)} + \dfrac{(z-y)^2}{(z-x)(x-y)} + \dfrac{(x-z)^2}{(x-y)(y-z)} }{3} &\ge& \sqrt[3]{1} \\ \dfrac{\dfrac{(y-x)^2}{(y-z)(z-x)} + \dfrac{(z-y)^2}{(z-x)(x-y)} + \dfrac{(x-z)^2}{(x-y)(y-z)} }{3} &\ge& 1 \\ \dfrac{(y-x)^2}{(y-z)(z-x)} + \dfrac{(z-y)^2}{(z-x)(x-y)} + \dfrac{(x-z)^2}{(x-y)(y-z)} &\ge& 1\times 3 \\ \dfrac{(y-x)^2}{(y-z)(z-x)} + \dfrac{(z-y)^2}{(z-x)(x-y)} + \dfrac{(x-z)^2}{(x-y)(y-z)} &\ge& 3 \\ \hline \end{array}$$

The smallest possible value is $$\mathbf{3}$$

Mar 9, 2020
edited by heureka  Mar 9, 2020