+0

# Help! Thanks! :)

0
38
1

Let n be the integer such that $$0 \le n < 31$$ and $$3n \equiv 1 \pmod{31}$$. What is $$\left(2^n\right)^3 - 2 \pmod{31}$$?

Express your answer as an integer from 0 to 30, inclusive.

Dec 14, 2020

### 1+0 Answers

#1
0

3n mod 31 = 1, solve for n

n = 31m  +  21, where m =0, 1, 2, 3........etc.

The smallest n = 21

[(2^21)^3  -  2] mod 31 == 6

Dec 14, 2020