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Find the smallest value of x such that \(x^2 + 10x + 25 = 8\).

 Feb 4, 2021
 #1
avatar+1764 
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x^2 + 10x + 25 = 8

x^2 + 10x + 17 = 0

 

Plug in quadratic equation:  https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:quadratic-functions-equations/x2f8bb11595b61c86:quadratic-formula-a1/v/using-the-quadratic-formula 

-5 +- 2 sqrt(2)

But we want the smallest, so our answer is -5 - 2sqrt(2) 

 

I hope this helped. :)))

 

=^._.^=

 Feb 4, 2021
 #2
avatar+268 
+1

This question can be turned into a quadratic equation.

 

x^2 + 10x + (25 - 8) = 0

x^2 + 10x + 17 = 0

 

Now we use the Quadratic formula

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a} \)

 

Using the formula, we can find the value of x which will be

x=−5+2√2 or x=−5−2√2

 

However, the question asked for the smallest value which is −5−2√2.

 

Hope that helps :) !!!

 

🙃🙃👌

 Feb 4, 2021
edited by IhaveOBJD  Feb 4, 2021
 #3
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0

Nice job both of you!

Guest Feb 4, 2021

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