Help Thanks!

x^2 + 10x + 25 = 8

x^2 + 10x + 17 = 0

Plug in quadratic equation:  https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:quadratic-functions-equations/x2f8bb11595b61c86:quadratic-formula-a1/v/using-the-quadratic-formula 

-5 +- 2 sqrt(2)

But we want the smallest, so our answer is -5 - 2sqrt(2) 

I hope this helped. :)))

=^._.^=

This question can be turned into a quadratic equation.

x^2 + 10x + (25 - 8) = 0

x^2 + 10x + 17 = 0

Now we use the Quadratic formula

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a} \)

Using the formula, we can find the value of x which will be

x=−5+2√2 or x=−5−2√2

However, the question asked for the smallest value which is −5−2√2.

Hope that helps :) !!!

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