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# Help Thanks!

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Find the smallest value of x such that $$x^2 + 10x + 25 = 8$$.

Feb 4, 2021

#1
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x^2 + 10x + 25 = 8

x^2 + 10x + 17 = 0

-5 +- 2 sqrt(2)

But we want the smallest, so our answer is -5 - 2sqrt(2)

I hope this helped. :)))

=^._.^=

Feb 4, 2021
#2
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This question can be turned into a quadratic equation.

x^2 + 10x + (25 - 8) = 0

x^2 + 10x + 17 = 0

Now we use the Quadratic formula

$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$$

Using the formula, we can find the value of x which will be

x=−5+2√2 or x=−5−2√2

However, the question asked for the smallest value which is −5−2√2.

Hope that helps :) !!!

🙃🙃👌

Feb 4, 2021
edited by IhaveOBJD  Feb 4, 2021
#3
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Nice job both of you!

Guest Feb 4, 2021