If \(f(c)=\frac{3}{2c-3},\) find \(\frac{kn^2}{lm}\) when \(f^{-1}(c)\times c \times f(c)\) equals the simplified fraction\(\frac{kc+l}{mc+n}\), where \(k,l,m,\text{ and }n\) are integers.
(kc + l)/(mc + n) = 3/16.