+0  
 
+1
40
3
avatar+621 

For each part of this problem, convert the fraction to a "decimal" in the specified base.

(a) What is 1/2 in base 3?

(b) What is 1/7 in base 8?

(c) What is 1/(b-1) in base b?

Thanks! smileycoolsmiley

MIRB16  Apr 9, 2018
Sort: 

3+0 Answers

 #1
avatar+85726 
+2

(1/2)  to base 3

 

(1/2) * 3   =  3/2     ⇒  1  + 1/2

(1/2) * 3  =   3/2     ⇒  1  + 1/2

(1/2) * 3  =  3/2    ⇒   1  +  1/2

........

 

Read  the numbers  in red from bottom to top =  .111...3

 

(1/7) base  8  

 

(1/7) * 8  =  8/7   =  1  +  1/7

(1/7) * 8  = 8/7    =  1  + 1/7

(1/7) * 8  = 8/7   =    1 + 1/7

........

 

Read the red numbers from bottom to top  =  .111...8

 

So  it appears  that   1  / (b - 1)  in  base b  is  .111.....b

 

 

 

cool cool cool

CPhill  Apr 9, 2018
 #2
avatar+8 
0

1/2)  to base 3

 

(1/2) * 3   =  3/2     ⇒  1  + 1/2

(1/2) * 3  =   3/2     ⇒  1  + 1/2

(1/2) * 3  =  3/2    ⇒   1  +  1/2

........

 

Read  the numbers  in red from bottom to top =  .111...3

 

(1/7) base  8  

 

(1/7) * 8  =  8/7   =  1  +  1/7

(1/7) * 8  = 8/7    =  1  + 1/7

(1/7) * 8  = 8/7   =    1 + 1/7

........

 

Read the red numbers from bottom to top  =  .111...8

 

So  it appears  that   1  / (b - 1)  in  base b  is  .111.....b

 

 

 

  see im samtcheeky

itsurboyalex  Apr 9, 2018
 #3
avatar+418 
0

(1/2) * 3   =  3/2     ⇒  1  + 1/2

(1/2) * 3  =   3/2     ⇒  1  + 1/2

(1/2) * 3  =  3/2    ⇒   1  +  1/2

........

 

Read  the numbers  in red from bottom to top =  .111...3

 

(1/7) base  8  

 

(1/7) * 8  =  8/7   =  1  +  1/7

(1/7) * 8  = 8/7    =  1  + 1/7

(1/7) * 8  = 8/7   =    1 + 1/7

........

 

Read the red numbers from bottom to top  =  .111...8

 

So  it appears  that   1  / (b - 1)  in  base b  is  .111.....b

jakesplace  Apr 9, 2018

24 Online Users

avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details