f(a)=ax5+2. for example f(3)=3x5+2=17 evaluate f(10)
f(3)=3x5+2=17 solve this for 'x^5' first
3x^5 = 15
x^5 = 5 this is far enough
Now put in '10' for 'a'
10 (5) + 2 = 52 done.
Hi EP,
Your annser is right but you confused me by accidentaly using the power ^ notation.
\(f(a)=a* 5+2\\ f(a)=5a+2\\~\\ f(3)=5*3+2=17\\~\\ f(10)=5*10+2=52\)
+37147 
