f(a)=ax5+2. for example f(3)=3x5+2=17 evaluate f(10)
f(3)=3x5+2=17 solve this for 'x^5' first
3x^5 = 15
x^5 = 5 this is far enough
Now put in '10' for 'a'
10 (5) + 2 = 52 done.
Hi EP,
Your annser is right but you confused me by accidentaly using the power ^ notation.
f(a)=a∗5+2f(a)=5a+2 f(3)=5∗3+2=17 f(10)=5∗10+2=52
+37165 
