+0  
 
-4
629
1
avatar+12 

I can't be able to figure it this out.

 Jun 16, 2020
 #1
avatar+36915 
0

The angle that has tan = a/b. (Remember tan= opp/adj)    Is the angle at the lower right....cos of this angle would be adj/ hyp =b/ ((sqrta2+b2))

 Jun 16, 2020

1 Online Users

avatar