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Jim stands beside a wide river and wonders how wide it is. He spots a large rock on the bank directly across from him. He then walks upstream d = 65 strides and judges that the angle between him and the rock, which he can still see, is now at an angle of 30∘ downstream. Jim measures his stride to be about 0.8 m long.

 Jan 15, 2017

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 #1
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Guest
17 mins ago     

Jim stands beside a wide river and wonders how wide it is. He spots a large rock on the bank directly across from him. He then walks upstream d = 65 strides and judges that the angle between him and the rock, which he can still see, is now at an angle of 30∘ downstream. Jim measures his stride to be about 0.8 m long.

 

laugh

 Jan 15, 2017
 #1
avatar+12531 
+5
Best Answer


Guest
17 mins ago     

Jim stands beside a wide river and wonders how wide it is. He spots a large rock on the bank directly across from him. He then walks upstream d = 65 strides and judges that the angle between him and the rock, which he can still see, is now at an angle of 30∘ downstream. Jim measures his stride to be about 0.8 m long.

 

laugh

Omi67 Jan 15, 2017
 #2
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65 x 0.8 =52 meters - his distance upstream.

Cos(30) =52 / H

H = 52 / 0.8660254

H = 60.04 meters - the hypotenuse

Width of the river =W^2 =60.04^2 - 52^2

W = 30.02 meters - the width of the river.

Moderators: Please verify this. Thanks.

 Jan 15, 2017

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