At Disneyland they sell candy to fundraise for outside charities. They sell about 5500 candy bars at a profit of $0.75/each. Each $0.50 increase in the price will increase the profit of each candy bar by $0.50. However, they will sell about 1000 fewer candy bars.
A.) whAt is the profit for Disney if the profit is $0.75 per candy bar?
for my answer I got 5500(.75)= $4125
b.) find an equation for this model of the profit disney makes if they increase the price of each candy
bar by $0.50 “x” amount of times
my answer: p(x)=4500(.75)+0.50x
c.) use your model to determine the profit if the price per candy bar is increased by $1.00
my answer: 4500=0.50(2)+0.75
4500=$1.75
p=$2571.429
d.) what price increase will bring the school the highest profit?
Couldn’t figure this one out
E.) what is the highest profit?
Same with this one
+36916 I'd say you got A correct
B (5500-1000x) is the candy bars they will sell
(5500-1000x)(.75 + .50 x ) is the profit
4125 + 2750 x - 750x - 500x^2 = profit
-500 x^2 + 2000x + 4125 = profit
C 1 dollar is 50 (2) x= 2
-500(2^2) + 2000(2) + 4125 = $6125
D This equation is an upside down parabola
max = -b/(2a) = -2000/-1000 = 2 = x
E the profit will be as found for x = 2 in C
Here is the graph :
+128474 At Disneyland they sell candy to fundraise for outside charities. They sell about 5500 candy bars at a profit of $0.75/each. Each $0.50 increase in the price will increase the profit of each candy bar by $0.50. However, they will sell about 1000 fewer candy bars.
A is correct
B Let x be the number of .50 increases....and for each N, they sell 1000 fewer candy bars
So we have
Profit = Quantity * Price
Profit = ( 5500 - 1000x) (.75 + .50x)
C If they increase the price by 1.00, x = 2 and we have
Profit = (5500 - 1000 (2) ) ( .75 + .50(2) ) =
(3500) ( 1.75) = $6125
D Let us simplify the function as
Profit = 4125 - 750x + 2750x - 500x^2 = - 500x^2 + 2000x + 4125
We have the form Ax^2 + Bx + C
A = -500 B = 2000
The number of x increases that maximize the profit is given by
-B / [ 2A] = -2000 / [ 2 * -500] = 2000 / 1000 = 2 increases
E So...a $ 1.00 increase maximizes the profit...and we have seen that this profit is $6175
Here's a graph to show this : https://www.desmos.com/calculator/lhabxwm2yz
