5^ -3 divided by 10^ -2
it's almost identical to the last one
\(\dfrac{5^{-3}}{10^{-2}} = 5^{-3}\cdot 10^2 = \\ 5^{-3}\cdot 5^2\cdot 2^2 = 5^{-1}\cdot 2^2 = \\ \dfrac{4}{5}\)
thx soo much
5^-3 / 10^-2 = 10^2 / 5^3 = 100/125 = 4/5
